Question

jumbo Jet of mass 4 × 10^5 kg travelling at a speed of 500 m/s lands on airport it takes two minutes to come in rest calculate average force applied by ground on aeroplane?​

Answer 1

Need to FinD :-

• Average force applied by ground on aeroplane .

$\red{\frak{Given}}\begin{cases}\textsf{ Mass of jumbo jet is 4 \times 10 ^{\sf 5} kg .}\\\textsf{ It is travelling with speed of 500m/s .}\\\textsf{ It takes two Minutes to come in rest . }\end{cases}$

We know that force is rate of change of Momentum or simply product of mass and acceleration. Here the initial Velocity of the plane is 500m/s and the Final exams is 0m/s.

• Using this formula of Force we have ,

$\sf:\implies Force = \dfrac{\Delta p }{t} = ma \\\\\sf:\implies Force = m \dfrac{ v - u }{t} \\\\\sf:\implies Force = 4\times 10^5 kg\bigg( \dfrac{0m/s - 500m/s}{2\ min }\\\\\sf:\implies Force = 4\times 10^5kg \dfrac{-500 m/s}{120s } \\\\\sf:\implies Force = 4.166 \times 4 \times 10^5 \\\\\sf:\implies\underset{\blue{\sf Required\ Force }}{\underbrace{\boxed{\pink{\frak{ Force = 1.67 \times 10^{6}\ N }}}}}$

Answer 2

Answer:

given, mass= 4*10^5 kg, u=5000m/s

Explanation: