jump between successive ionization energy is maximum when :-
a) I.E. 1 to I.E. 2
b) I.E. 2 to I.E. 3
c) I.E. 3 to I.E. 4
d) I.E. 4 to I.E. 5
Answers
To Determine: Identify the unknown element from the ionization energy data given.Answer: The unknown element is option (c) silicon.Explanation:The amount of energy required to remove one electron from the valence shell of an atom in the gaseous state is called first ionization energy. The amount of energy required to remove the second electron from the valence shell of an atom in the gaseous state is called second ionization energy so on.From the successive ionization energy data, an unknown element can be identified as the successive ionization energy data gives information about the electronic configuration of the element. The successive ionization energy increases uniformly with the removal of each electron. However, a large change is shown when a core electron is removed.The ionization energy data shows that a sudden increase in the ionization energy in going from to indicate that the element must contain four valence electrons and the fifth electron is being removed from the core shell. The element with such electronic configuration is silicon.The electronic configuration of silicon
Tuples are immutable i.e the value cannot be changed. So, Option D is correct.