Question

Junhao's sister is 5 years old. She is 36 years younger than their mother. In how many years' time will their mother's age be 4 times her age?
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Answer 1

• GIVEN:-

Junhao's sister is 5 years old.

She is 36 years younger than her mother.

• To Find:-

In how many years' time will her mother's age be 4 times her age?

• SOLUTION:-

Junhao's age is 5.

Then, her mother's age = 36 + 5 = 41

Let after x years, her mother will be 4 times her age.

After x years:

Age of Junhao = 5 + x

Age of her mother = 41 + x

According to question,

⇒ 41 + x = 4(5 + x)

⇒ 41 + x = 20 + 4x

⇒ 4x - x = 41 - 20

⇒ 3x = 21

⇒ x = 7 years

• Let's verify it:-

Junhao's age will be 5 + 7 = 12.

Her mother's age will be 41 + 7 = 48.

Her mother's age is 4 times of Junhao (12 × 4 = 48).

$\large\purple\therefore\boxed{\sf{\purple{After\:7\:years\:Junhao's\:age\:will\:be\:4\:times\:her\:age.}}}$

Answer 2

Answer:

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Step-by-step explanation:

GIVEN:-

Junhao's sister is 5 years old.

She is 36 years younger than their mother.

To Find:-

In how many years' time will her mother's age be 4 times her age?

SOLUTION:-

Junhao's age is 5.

Then, her mother's age = 36 + 5 = 41

Let after x years, her mother will be 4 times her age.

After x years:

Age of Junhao = 5 + x

Age of her mother = 41 + x

According to question,

⇒ 41 + x = 4(5 + x)

⇒ 41 + x = 20 + 4x

⇒ 4x - x = 41 - 20

⇒ 3x = 21

⇒ x = 7 years

Let's verify it:-

Junhao's age will be 5 + 7 = 12.

Her mother's age will be 41 + 7 = 48.

Her mother's age is 4 times of Junhao (12 × 4 = 48).

\large\purple\therefore\boxed{\sf{\purple{After\:7\:years\:Junhao's\:age\:will\:be\:4\:times\:her\:age.}}}∴

After7yearsJunhao

′

sagewillbe4timesherage.