Math, asked by mayank231124, 2 months ago

JUON ULV.)
A man bought two horses for Rs 25000 each. He sold them gaining 25% on the first and losing 25% on the second. In the whole transaction there is
Options
O 6 62% loss
4 % gain
no loss no gain
none of these​

Answers

Answered by BrainlyTwinklingstar
2

Correct Question

A man bought two horses for Rs 25000 each. He sold them gaining 25% on the first and losing 25% on the second. In the whole transaction there is

• 62% loss

• 4% gain

• No loss, no gain.

• None of these

Given :

Cost price of one horse (each) :- ₹25000

Gain of one horse :- 25%

Loss of one horse :- 25%

To find :

Loss or gain percent of whole transaction.

Solution :

First we should find the cost price of each horses

Cost price of first horse :

{\sf \dashrightarrow \dfrac{100}{100 + Profit \%} \times SP}

{\sf \dashrightarrow \dfrac{100}{100 + 25} \times 25000}

{\sf \dashrightarrow \dfrac{100}{125} \times 25000}

{\sf \dashrightarrow \dfrac{4}{5} \times 25000}

{\sf \dashrightarrow \dfrac{4 \times 25000}{5} = \dfrac{100000}{5}}

{\sf \dashrightarrow \cancel \dfrac{100000}{5} = 20000}

Cost price of second horse :

{\sf \dashrightarrow \dfrac{100}{100 - Loss \%} \times 25000}

{\sf \dashrightarrow \dfrac{100}{100 - 25} \times 25000}

{\sf \dashrightarrow \dfrac{100}{75} \times 25000}

{\sf \dashrightarrow \dfrac{4}{3} \times 25000}

{\sf \dashrightarrow \dfrac{4 \times 25000}{3} = \dfrac{100000}{3}}

{\sf \dashrightarrow \cancel \dfrac{100000}{3} = 33333.33}

Total cost price :

{\sf \dashrightarrow 20000 + 33333.33}

{\sf \dashrightarrow 53333.33}

Total selling price :

{\sf \dashrightarrow 25000 + 25000}

{\sf \dashrightarrow 50000}

Loss percentage :

{\sf \dashrightarrow \dfrac{53333.33 - 50000}{53333.33} \times 100}

{\sf \dashrightarrow \dfrac{3333.33}{53333.33} \times 100}

{\sf \dashrightarrow \dfrac{3333.33 \times 100}{53333.33} = \dfrac{333333}{53333.33}}

{\sf \dashrightarrow 6.24 \%}

Hence, the loss percentage on whole transaction is 6.24%.

Correct option is none of these.

Similar questions