jupiter has a mass 318 times that of earth and its radius is 11.2 times that of earth's radius.estimate the escape velocity of a body from jupiter's surface given that the escape velocity from the earth's surface is 11.2km/s.Please do no give links.
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M = the mass
R = the radius of the Earth
M' = mass of jupiter
R' = radius of the Jupiter
thenM' = 318 M
R' = 11.2 RAlso, the escape velocity on the Earth, Ve = 11.2 km/sLet Ve' be the escape velocity on the Jupiter.Then,
Ve'/ Ve = √2GM'/ R' x √R/2GM
= √R/R' x M'/M
Ve'= Ve √R/R' x M'/M
= 11.2 x √R/ 11.2R x 318M/M
= 11.2 x √318/ 11.2
=59.68 km/s
R = the radius of the Earth
M' = mass of jupiter
R' = radius of the Jupiter
thenM' = 318 M
R' = 11.2 RAlso, the escape velocity on the Earth, Ve = 11.2 km/sLet Ve' be the escape velocity on the Jupiter.Then,
Ve'/ Ve = √2GM'/ R' x √R/2GM
= √R/R' x M'/M
Ve'= Ve √R/R' x M'/M
= 11.2 x √R/ 11.2R x 318M/M
= 11.2 x √318/ 11.2
=59.68 km/s
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