Question

jura has called an Unsaturated solution
Rohini tested the solubility of five substances at
different temperatwo. She noted the amount of each
substanca dissolved in 100 g of watertor form saturated
solution at particular temporature and reported
the following data
Substance T
Temperature
dissolved. I 25C 306 Soc
21.4 23-8
25
35
7.9
7.6
36.2 140.6
7 45.4
32 1 62
8.2
soluble in water at 20c?
a)
Which
is least
substance? ​

Answer 1

Answer:

here is your answer

Explanation:

ANSWER

(a) At 313 K 62 g of potassium nitrate dissolved in 100 g of water. So to produce a saturated solution of potassium nitrate in 50 g of water we need  

100

62

​  

×50=31 g of potassium nitrate.

(b)Some soluble potassium chloride will separate out in the form of crystal at room temperature because the solubility of potassium chloride will decrease.

(c)

(i)  Solubility of Potassium nitrate at 293 K is 32 g.

(ii)  Solubility of sodium chloride at 293 K is 36 g.

(iii) Solubility of Potassium chloride at 293 K is 35 g.

(iv) Solubility of Ammonium chloride at 293 K is 37 g.                                                      

The solubility of Ammonium chloride is highest at this temperature.

(d)The solubility of salt increases with the increase in temperature.