Math, asked by Handsomebuddy, 1 year ago

just give me a BASIC IDEA how to solve. ....

only idea..

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Answers

Answered by NidhraNair
13
hello...

hint / idea -

Just take log..

then generate 10 both sides...

you will get answer as (c)
i.e 6603

thank you....


NidhraNair: fine..
Handsomebuddy: thank you..
Handsomebuddy: doe idea
Handsomebuddy: for
NidhraNair: welcome ☺
Tushakar: OK its fine
Tushakar: I can do it
siddhartharao77: chelli - Answer (C) - 6603
Tushakar: no bro
Tushakar: answer is 6602
Answered by siddhartharao77
12
Answer:

Option - C.

Explanation:

Let x = 2000^2000.


Apply log on both sides, we get

= > log x(base 10) = log 2000^2000(base 10)

= > log x(base 10) = 2000 log2000(base 10)

= > log x = 2000 * log 2 * 1000

= > log x = 2000(log 2 + log 1000)

= > log x = 2000(0.3010 + 3)

= > log x = 6602.


Therefore the number of digits = logx + 1

                                                     = 6602 + 1

                                                     = 6603.


Hope this helps!

siddhartharao77: I mean number of digits...
Tushakar: ok
Tushakar: Thank you very much
siddhartharao77: :-)
siddhartharao77: Sorry to say..In the beginning i used to ask the same doubts..But if u keep on studying log functions, u will get it.
Tushakar: no bro
Tushakar: don't be sorry
Tushakar: it's not your fault
Tushakar: thanks for explaining me
siddhartharao77: :-)
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