just give me a BASIC IDEA how to solve. ....
only idea..
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Answered by
13
hello...
hint / idea -
Just take log..
then generate 10 both sides...
you will get answer as (c)
i.e 6603
thank you....
☺
hint / idea -
Just take log..
then generate 10 both sides...
you will get answer as (c)
i.e 6603
thank you....
☺
NidhraNair:
fine..
thank you..
doe idea
for
welcome ☺
OK its fine
I can do it
chelli - Answer (C) - 6603
no bro
answer is 6602
Answered by
12
Answer:
Option - C.
Explanation:
Let x = 2000^2000.
Apply log on both sides, we get
= > log x(base 10) = log 2000^2000(base 10)
= > log x(base 10) = 2000 log2000(base 10)
= > log x = 2000 * log 2 * 1000
= > log x = 2000(log 2 + log 1000)
= > log x = 2000(0.3010 + 3)
= > log x = 6602.
Therefore the number of digits = logx + 1
= 6602 + 1
= 6603.
Hope this helps!
Option - C.
Explanation:
Let x = 2000^2000.
Apply log on both sides, we get
= > log x(base 10) = log 2000^2000(base 10)
= > log x(base 10) = 2000 log2000(base 10)
= > log x = 2000 * log 2 * 1000
= > log x = 2000(log 2 + log 1000)
= > log x = 2000(0.3010 + 3)
= > log x = 6602.
Therefore the number of digits = logx + 1
= 6602 + 1
= 6603.
Hope this helps!
I mean number of digits...
ok
Thank you very much
:-)
Sorry to say..In the beginning i used to ask the same doubts..But if u keep on studying log functions, u will get it.
no bro
don't be sorry
it's not your fault
thanks for explaining me
:-)
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