Question

Just select the correct answer. You will be awarded the award.

Answer 1

Answer:

0 is the answer loga^3+b^3/(a+b)(a^2+b^2-ab)=

log(a^3+b^3)/(a^3+b^3)=log1=0

Answer 2

Answer:

c) 0

Step-by-step explanation:

Weknow that,

a³+b³=(a+b)(a²+b²-ab)   ......(1)

So,

log(a³+b³)-log(a+b)-log(a²+b²-ab)   ......(2)

Putting value of (a³+b³) from (1) in (2) , we get

=log[(a+b)(a²+b²-ab)]-log(a+b)-log(a²+b²-ab)

[Formula; log(mn)=log m+log n]

=log(a+b)+log(a²+b²-ab)-log(a+b)-log(a²+b²-ab)

=0

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