Question

Just solve this. I really need this.

Answer 1

❗ ANSWER ❗

I think d option is the correct answer

Hope it's helpful dear...............

❌ Itz Mahi Here ❌

Answer 2

$\star\:\:\:\bf\large\underline\blue{Question:-}$

• For $f(x) =x^{2}-1$, if $a=f(f(f(0)))$ and $b = 4( \sin53 \degree \tan37 \degree \sec53 \degree)$,then find the value of $a + b$

$\star\:\:\:\bf\large\underline\blue{Solution:-}$

First of all, we will find the value of a and b and then we will add then up.

So,

$a = f(f(f(0)))$

$= f(f( {0}^{2} - 1 ))$

$= f(f( - 1))$

$= f( {( - 1)}^{2} - 1)$

$= f(1 - 1)$

$= f(0)$

$= {0}^{2} - 1$

$= - 1$

So,

$a = - 1$

Now,

$b = 4( \sin53 \degree \tan37 \degree \sec53 \degree)$

Now, we will calculate b.

$4( \sin53 \degree \tan37 \degree \sec53 \degree)$

$= 4( \frac{ \sin53 \degree}{ \cos53 \degree \times \cot37 \degree } )$

$= 4( \frac{ \tan53 \degree}{ \cot37 \degree } )$

$= 4 \times ( \tan53 \degree \times \tan37 \degree)$

$= 4 \times ( \tan53 \degree \times \tan(90 \degree - 53 \degree))$

$= 4 \times ( \tan53 \degree \times \cot53\degree)$

$= 4 \times 1$

$= 4$

So,

$b = 4$

So,

$a + b = - 1 + 4 = 3$

$\star\:\:\:\bf\large\underline\blue{Answer:-}$

• Correct option is (a).