just tell me how to solve now ??shall i multiply the power outside the bracket to the inner ones?
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Step-by-step explanation:
(3^5/3^7) ^ (5-7)
= {3^(5-7)/1} ^ -2
={3^-2/1} ^ -2
=(1/9) ^ -2
=81
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(3^5/3^7) ^5-7
(3^5/3/^7) -³
(3^5-7)-³
(3^-³) -3
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