Justification of 15 degree angle
shivam9889:
tell me it is made of compass and protractor then I will answer
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if angle ACB equals to angle BCE
it IS the bisector of angles
it IS the bisector of angles
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How to construct a 15 degree angle with a compass?
How to construct a 15 degree angle with a compass?
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person
:- MM POOVANNA
*To construct 15^0 angle follow these steps:
*Draw a ray L of any length.
*Taking centre as O draw an arc with any radius to cut the line L.
*Label the intersecting point of L and the arc as B.
*Taking centre as B draw an arc with the same radius taken before to cut the previous arc at C.
*Join O and C and \angle COA=60^0
*Draw an angle bisector OD to the \angle COA and \angle DOB=30^0
*Draw an angle bisector OE to the \angle DOB and \angle EOB=15^0 is our required angle.
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