justification of 60 degree angle??
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Answered by
17
An equilateral triangle has all three interior angles 60°.
⇒ Draw a straight line, PQ that will be one leg of the angle.
⇒ With a compass on P, Set the width half of PQ
⇒ Draw an arc above P and crossing PQ
⇒ Where the arc crosses PQ, make an arc across the first.
⇒ Draw a straight line toward the x.
⇒ Draw a straight line, PQ that will be one leg of the angle.
⇒ With a compass on P, Set the width half of PQ
⇒ Draw an arc above P and crossing PQ
⇒ Where the arc crosses PQ, make an arc across the first.
⇒ Draw a straight line toward the x.
nawalmodanigmailcom:
i know the construction thanxx for that but i need the justification . how to prove its 60 degree...?
oh. opps
Let me edit my answer then
Answered by
42
join DE ( pt at the base and 60 degree pt...u will get ADE as triangle )
AD=AE(radii of same arc) - 1ST
AD=DE(arc of same radius) - 2ND
from 1 and 2
AD=AE=DE
in triangle as all the 3 sides are equal..therefore it is an equilateral triangle...
A=E=D=x
by angle sum property of triangle,
A+E+D=180
3x=180
x=180/3
x=60
therefore A=E=D=60
AD=AE(radii of same arc) - 1ST
AD=DE(arc of same radius) - 2ND
from 1 and 2
AD=AE=DE
in triangle as all the 3 sides are equal..therefore it is an equilateral triangle...
A=E=D=x
by angle sum property of triangle,
A+E+D=180
3x=180
x=180/3
x=60
therefore A=E=D=60
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