Question

Justify that (x²+1)²-x² has no real roots

Answer 1

Answer:

Step-by-step explanation:

(x²+1)² = x²

x²+1 = x

x²-x+1= 0

Discriminant = b²-4ac

= (-1)² -(4)(1)(1)

= 1-4

=-3

As d<0

Hence, the equation has no real roots.