Justify the presence of 18 elements in 4th period of periodic table?
Answers
Answered by
99
When we consider —
n = 4,
the orbitals 3d, 4s and 3p present in the (form of) outermost shells show the order of their increasing energies — i.e. 3p<4s<3d.
Since the total number of orbitals available are 9 (1 from 4s, 3 from 3p & 5 from 3d orbital), the maximum number of electrons that can occupy the three orbitals is 18.
Henceforth, 18 elements should be present in the 4th period.
n = 4,
the orbitals 3d, 4s and 3p present in the (form of) outermost shells show the order of their increasing energies — i.e. 3p<4s<3d.
Since the total number of orbitals available are 9 (1 from 4s, 3 from 3p & 5 from 3d orbital), the maximum number of electrons that can occupy the three orbitals is 18.
Henceforth, 18 elements should be present in the 4th period.
Answered by
58
When n = 4, we find that in the orbitals 3d, 4s and 3p which are present in
the outermost shells have energies in increasing order — i.e. 3p<4s<3d.
Total number of orbitals = 9 (1 from 4s, 3 from 3p & 5 from 3d orbital),
So, maximum number of electrons found in the three orbitals is 9X2 = 18.
Therefore, 4th period should have 18 elements.
Total number of orbitals = 9 (1 from 4s, 3 from 3p & 5 from 3d orbital),
So, maximum number of electrons found in the three orbitals is 9X2 = 18.
Therefore, 4th period should have 18 elements.
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