Question

justify whether it is true to say that the following are the Nth term of an ap 2 n minus 3 and n square + 1​

Answer 1

(i) Yes, here an = 2n - 3
Put n = 1, a1 = 2(1) -3 = -1
Put n = 2, a2 = 2(2) -3 = 1
Put n = 3, a3 = 2(3) -3 = 3
Put n = 4, a4 = 2(4) -3 = 5
List of numbers becomes -1,1,3,...
Here, a2 - a1 = 1 - (-1) = 1 + 1 = 2
a3 - a2 = 3 - 1 = 2
a4 - a3 = 5 - 3 = 2
∵ a2 - a1 = a3 - a2 = a4 - a3 = ...
Hence, 2n - 3 is the nth term of an AP.
(ii) No, here an = 3n2 + 5
Put n = 1, a1 = 3(1)2 + 5 = 8
Put n = 2, a2 = 3(2)2 + 5 3(4) + 5 = 17
Put n = 3, a3 = 3(3)2 + 5 3(9) + 5 = 27 + 5 = 32


Maybe your answer is right
And sry also