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taking firstly x=2
p(x)= x³-2x²
p(x)= (2)³-2×(2)²
p(x)= 8-8
p(x)= 0
similarly,
p(x)= 0 ,when taking x=0
hence proved 2,0 are zeroes of the polynomial x³-2x²
Answered by
0
taking firstly x=2
p(x)= x³-2x²
p(x)= (2)³-2×(2)²
p(x)= 8-8
p(x)= 0
similarly,
p(x)= 0 ,when taking x=0
hence proved 2,0 are zeroes of the polynomial x³-2x²
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