Jyoti and dhani together can do a piece of work in 6 days and b alone can do the same work in 9 days in how many days can Jyoti alone complete the work
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18 days
Step-by-step explanation:
(J + D )=> 6 days & D alone => 9 days
T.w = LCM(9,6) = 18 units
efficiency of (J+D) = 18/6 = 3 units/day
efficiency of D = 18/9 = 2 units /day
efficiency of J = 3-2 = 1 units/day
J alone = 18/1 = 18 days
2nd method:
work is same in both cases
W1 = W2
(J + d)×6 = 9d => 6J = 3d => j/d = 1/2
Total work = 9d = 9(2) = 18 units
J alone = 18/1 = 18 days
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