Question

Jyoti take a loan of 6000 and pays back 7,080 at the end of three years. What is the rate of interest that she paid ? ​

Answer 1

Answer:

6%

Step-by-step explanation:

principal= 6000

amount = 7080

time =3 years

now,

amount = principal + interset

interest = amount- principal

interest= 7080-6000

interest= 1080

again,

Rate= Interest ×100 ÷ PT

= 1080× 100÷ 6000× 3

= 108000÷ 18000

= 6 %

Answer 2

Given :

• Jyoti take a loan of ₹6000
• She pays back ₹7080 at the end of Three years　

To Find :

• Rate of interest that she paid　

 

Solution :

• Jyoti paid ₹(7080 – 6000) = 1080 as interest

　　

$\dag\large\rm\underline\pink{As\:we\:know\:that\::}$

　　

• SI = 1080

　　

• T = 3 years

　　

• P = ₹6000

　　

Therefore, We need to find R

　　

The formula for S.I is :

　　　　

$\large\sf SI = \frac{P \times R \times T}{100}$

　　　　

$\large\sf R = \frac{SI \times 100}{P \times T}$

　　

　　

$\star\large\mathfrak \purple{\:Substituting\:the\:values}$

　　　　

$\large\sf R = \frac{1080 \times 100}{6000 \times 3} = 6$

　　

$\star\rm\underline\red{Hence,\: Jyoti\:paid\:interest\:at\:rate\:of\:6\%}$