(k,0),(3,4),(5,-2) is 10 sq.unit then find k
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Answer:
K=6
Step-by-step explanation:
A(K,0) B(3,4) C(5,-2)
area of ABC=(K(4+2)+3 (-2-0)+5 (0-4)
10 =(K(6)+3 (-2)+5 (-4)
10 =(6K-6-20)
10 =6K-26
10+26=6K
36=6K
K=6
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