Question

( k-1 ) ( 2k-1 ) - ( 2k - 1) = 0 find

Answer 1

( k-1 ) ( 2k-1 ) - ( 2k - 1) = 0

2k^2-2k -k +1 -2k +1 =0

2k^2 -5k +2 =0

Answer 2

Heya, here's ur answer

Answer

k=0

Step-by-step explanation:

( k-1 ) ( 2k-1 ) - ( 2k - 1) = 0

(2k-1)[k-1-(-1)]=0

k(2k-1)=0

k=0/(2k-1)

k=0

Hope this helps!!!