Math, asked by hemantarijal579com, 3 months ago

k) 1+tan 4A. tan 2A = sec 4A​

Answers

Answered by ravi2303kumar
4

Step-by-step explanation:

to prove 1+tan 4A. tan 2A = sec 4A​

LHS = 1+tan 4A. tan 2A

       = 1 + \frac{sin4A}{cos4A}*\frac{sin2A}{cos2A}

       = \frac{cos4Acos2A+sin4Asin2A}{cos4Acos2A}

       = \frac{cos(4A-2A)}{cos4A*cos2A}

       = \frac{cos2A}{cos4A*cos2A}

       = \frac{1}{cos4A}

       = sec4A

       = RHS

=> LHS = RHS

Hence proved

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