Question

(k+1)x^2-2(3k+1)x+8k+1=0 find the value of k if the eqation has equal roots

Answer 1

here is ur answer....
plz follow me and Mark my answer as brainliest.....

Answer 2

here the equation has real and equal roots

therefore, D = 0

this implies (-2(3k+1)) - 4(k+1)(8k+1) = 0

from this we get,

4k - 12k = 0

4k(k - 3) = 0

k- 3 = 0

therefore k=3...

k = 3

__________________

easy one