Question

(k+1)x^2+(3k+1=x-7=0 Find k roots are equal​

Answer 1

Answer

put x:-1

(k+1) 1+(3k+1)=1-7=0

1k+(3k+1)=6=0

4k+6-1=0

4k+5=0

4k=0-5

4k=5

k=4-5=1

k=1 ans