Question

(k+1)x^2-4kx+9=0 have real and equal roots?find k​

Answer 1

real and equal roots

16 k^2 =4(k+1)(9)

4k^2 = 9k.+ 9

4k^2 -9k -9 = 0

4k^2 -12k +3k -9 =0

4k( k-3) +3(k-3) = 0

(4k+3)( k-3) = 0

k= 3,-3/4

brainliest pls

Answer 2

Answer:

The quadratic equation x^2 + 4kx+2(k+1) = 0 has equal roots, find the possible values of k. For a quadratic equation ax^2 +bx +c = 0 with equal roots we know the discriminant b^2-4ac must equal 0.