Question

K+1)x^2-4kx+9=0 have real and equal roots?Find k

Answer 1

(k+1)x^2 - 4kx + 9 = 0

A = k +1

B = -4k

C = 9

D = 0, For Real and Equal Roots

B^2 - 4AC = 0

(-4k)^2 - 4(k + 1) (9) = 0

16k^2 - 4(9k + 9) = 0

16k^2 - 36k - 36 = 0

4(4k^2 - 9k - 9) = 0

4k^2 - 9k - 9 = 0

4k^2 - 12k + 3k - 9 = 0

4k(k - 3) + 3(k - 3) = 0

(4k+3)(k-3) = 0

k = -3/4 and k = 3

Answer 2

Answer:

I am sorry

I don't know the answer