Question

(k+1)x+2y=5,3x+ky=7. ​

Answer 1

$\underline{ \boxed{\mathbb{\red{⛄answer♡࿐⛄}}}}</p><p>.$

$\\ for \: no \: solution \\ \frac{k + 1}{3} = \frac{2}{k } \\ k (\: k + 1) = 3 \times 2 \\ {k}^{2} + k = 6 \\ {k}^{2} + k - 6 = 0 \\ {k}^{2} + 3k - 2k - 6 = 0 \\ k(k + 3) - 2(k + 3) = 0 \\ (k - 2)(k + 3) = 0 \\ k - 2 = 0 \: or \: k + 3 = 0 \\ k = 2 \: or \: k = - 3$

Step-by-step explanation:

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