Math, asked by uppadagiri53135, 5 months ago

(k + 1)x + (k + 2)y + 5 = 0

Answers

Answered by niral

2

Answer:

Mark as brainliest answer.

Step-by-step explanation:

→ (k + 1)x + (k + 2)y + 5 = 0

→ kx + x + ky + 2y + 5 = 0

→ k(x+y) + x + 2y + 5 = 0

→ lhs ≠ rhs

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