Question

(k+1) x2—2 (3k+1) x +8k+1=0​

Answer 1

Answer:

${\huge{\underline{\underline{\mathfrak{\pink{Good Afternoon:-}}}}}}$

Here the equation has real and equal roots

therefore, D = 0

this implies (-2(3k+1)) - 4(k+1)(8k+1) = 0

from this we get,

4k - 12k = 0

4k(k - 3) = 0

k- 3 = 0

therefore k=3...

k = 3

Answer 2

This not the subject of English