Question

(k+1)x² - 2(k-1)x + 1 = 0 then find k if D=0 and formula of D = b²- 4ac.

Answer 1

Step-by-step explanation:

(k+1)x2 - 2(k-1)x + 1 = 0

Comparing the following equation with ax2+bx+x=0

a=k+1 b=2(k-1) c=1

∆ = b2-4ac

2(k-1)2 - (4)(k+1)(1)

(2k-2)2 - 4k+4

2k2-(2)(2k)(2)+(2) (2)-4k+4

4k-8k+4-4k+4

-8k+8

-8k=-8

-8÷-8=k

1=k

K=1