Question

(k+1)x²-2(k+4)x+2k = 0 find K​

Answer 1

Answer:

Let any given quadratic equation beax² + bx + c = 0 ..... (1)

For equal roots, we havediscriminant = 0i.e., b² - 4ac = 0

The given equation isx² + 2 (k + 1)x + k² = 0

Comparing with equation (1),

we geta = 1, b = 2 (k + 1), c = k²For equal roots,b² - 4ac = 0or, {2 (k + 1)}² - 4 * 1 * k² = 0or, 4 (k² + 2k + 1) - 4k² = 0or, 4k² + 4 (2k + 1) - 4k² = 0or, 4 (2k + 1) = 0or, 2k + 1 = 0

or, k = - 1/2

or, k = - 1/2Therefore, the value of k is (- 1/2)