Question

(k-1) x²+kx + 1=3 find k. Please help me fast ​

Answer 1

Step-by-step explanation:

Zero of the polynomial = -3

p(-3) = (k-1) x (-3)²+k x -3 +1 =0

( k -1)9 -3k + 1 = 0

9k - 9 - 3k + 1 =0

6k - 8 =0

6k = 8

k = 8/6

= 4/3

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Answer 2

Answer:

Zero of the polynomial = -3

p(-3) = (k-1) x (-3)²+k x -3 +1 =0

( k -1)9 -3k + 1 = 0

9k - 9 - 3k + 1 =0

6k - 8 =0

6k = 8

k = 8/6

= 4/3

Hope it helps..

Mark me as brainlist

Step-by-step explanation: