(k-1) x²+kx + 1=3 find k. Please help me fast
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Answered by
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Step-by-step explanation:
Zero of the polynomial = -3
p(-3) = (k-1) x (-3)²+k x -3 +1 =0
( k -1)9 -3k + 1 = 0
9k - 9 - 3k + 1 =0
6k - 8 =0
6k = 8
k = 8/6
= 4/3
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Answered by
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Answer:
Zero of the polynomial = -3
p(-3) = (k-1) x (-3)²+k x -3 +1 =0
( k -1)9 -3k + 1 = 0
9k - 9 - 3k + 1 =0
6k - 8 =0
6k = 8
k = 8/6
= 4/3
Hope it helps..
Mark me as brainlist
Step-by-step explanation:
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