Question

(k-12)x+2(k-12) l +12​

Answer 1

Step-by-step explanation:

ForequalrootsD=0

[2(k−12)]2−4.(k−12).2=0

$$\\4(k-12)^2-4(k-12)\times\2=0$$

k2−24k+144−2k+24=0

ork2−26k+168=0

k2−14k−12k+168=0

k(k−14)−12(k−14)=0(k−12)(k−14)=0∴k=12or14∴k=14(ask=12giveninquestion)