Question

(K-12)x^ + (2k-12)x + 2 =0
Then what is value of k ??
If it has equal roots

Answer 1

Answer:

D=0

b^{2} - 4ac

a=[k-12]

b=2k-12

c=2

[k-12]^{2} - 4 [2k-12] *2 =0

k^{2} +144-24k -[16k-96]=0

k^{2} +40k +240=0

find them by middle term splitting

Step-by-step explanation