Question

k-2,3k,2k+1 are in Ap find k​

Answer 1

Answer:

if k-2,3k ,2k+1 are in ap

then, 3k-(k-2)=2k+1-3k

3k-k+2=-k+1

2k+2=-k+1

2k+k=1-2

3k=-1

k=-1/3

Answer 2

Answer:

Step-by-step explanation:

for Ap

3K - (K-2) = (2K+1) -3K

3K -K+2 = 2K +1 -3K

2K +2 = -K +1

2K +K = -2 +1

3K = -1

K = -1/3