Question

k^2+9=16k value of k=?
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Answer 1

$\huge{\underline{\mathbb{\pink{SOLUTION:-}}}}$

$\tt\large\red{Given\:Equation:-}$

${k}^{2} + 9 = 16k$

$\sf\large\green{Sol:-}$

${k}^{2} + 9 = 16k \\ {k}^{2} + 9 = {4k}^{2} \\ {k}^{2} - {4k}^{2} = ( - 9) \\ { - 3k}^{2} = - {3}^{2} \\ -3k = 3 \\ k = \frac{3}{-3} \\ k = -1$