Question

(k+2)x^2 - kx +6= 0 find k

Answer 1

Answer:

hello friend here ur answer

Step-by-step explanation:

(k+2)x^2-kx+6=o

kx^2+2x^2-kx+6=o

kx^2-kx+2x^2+6=o

kx(x-1) +2(x^2+3)=o

Answer 2

Answer:

Correct question includes 'if the given equation has equal root'.

for equal and real roots, discriminant = 0

discriminant is given by b^2 - 4ac.

Here,

a = k + 2

b = - k

c = 6

= > (-k)^2 - 4(k+2)(6) = 0

= > k^2 - 24k - 48k = 0

Using quadratic formula -

= > k = $12\pm\sqrt3$