Question

(k+2)x^2-kx+6=0

Please find the answer

Answer 1

Answer:

I will solve and answer

Answer 2

Answer:

Let's solve for k.

(k+2)(x²)−kx+6=0

Step 1: Add -2x^2 to both sides.

kx²−kx+2x²+6+−2x²=0+−2x²

kx²−kx+6=−2x²

Step 2: Add -6 to both sides.

kx²−kx+6+−6=−2x²+−6

kx²−kx=−2x²−6

Step 3: Factor out variable k.

k(x²−x)=−2x²−6

k=-2x²-6/x²-x