Question

(K+2)x²+Kx+4 find value of k using Quadratic equations

Answer 1

what are ur roots i mean less than zero,zero,or greater than zero first u give this inform

Answer 2

(K+2)x²+Kx+4

k=???

Quadratic Equation,

(K+2)x²+Kx+4 =0

General Equation,

ax^2 + bx + c = 0

a=k+2,

b=k

c=4

We know that,

b^2 - 4ac = 0

(K)^2-4(k+2)*(4)=0

k^2-(4k+8)*4=0

k^2-(16k+32)=0

k^2-16k-32=0   ====>b)

k=8+4√6,

k=8-4√6..