Question

k /(2k + 1) + 1 /4(k+1)^ 2 - 1 ​

Answer 1

Step-by-step explanation:

k/(2k+1)+1/4(k+1)²-1=0

k/(2k+1)+1/4(k²+1+2k)-1=0

k/(2k+1)+1/(4k²+4+8k)-1=0

[k(4k²+4+8k)+1(2k+1)-(2k+1)(4k²+4+8k)]/(2k+1)(4k²+4+8k)=0

4k³+4k+8k²+2k+1-8k³-4k-8k²-4k²-4-8k=0

-4k³-4k²-6k-3=0

-(4k³+4k²+6k+3)=0

4k³+4k²+6k+3=0