Math, asked by vadinmendes, 2 months ago

k(2k+5)=3

solve with step by step explanation​

Answers

Answered by harshitha202034
0

Answer:

 \large k(2k + 5) = 3 \\  \\  \large 2 {k}^{2}  + 5k = 3 \\  \\  \large 2 {k}^{2}  + 5k - 3 = 0 \\  \\  \large k =  \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}  \\  \\  \large k =  \frac{ - 5± \sqrt{ {5}^{2}  - 4 \times 2 \times  - 3} }{2 \times 2}  \\  \\  \large k =  \frac{ - 5± \sqrt{25 - ( - 24)} }{4}  \\  \\  \large k =  \frac{ - 5± \sqrt{25 + 24} }{4}  \\  \\  \large k =  \frac{ - 5± \sqrt{49} }{4}  \\  \\  \large k =  \frac{ - 5±7}{4}  \\  \\  \large k =  \frac{ - 5 + 7}{4}  \:  \:  \: or \:  \:  \: k =  \frac{ - 5 - 7}{4}  \\  \\  \large k =  \frac{2}{4}  \:  \:  \: or \:  \:  \: k =  \frac{ - 12}{4}  \\  \\  \boxed{ \large k =  \underline{ \underline{ \bf \frac{1}{2}}}  \:  \:  \: or \:  \:  \: k = \underline{ \underline{ \bf - 3}}}

Answered by Anonymous
5

REFER TO ATTACHMENT HOPE IT HELPS

NICE PFP

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