Question

k+3,k+2,3k-7 and 2k-3 are in proportion. find k

Answer 1

Answer:

The answer is -1 0r 5.

Step-by-step explanation:

Since k+3,k+2,3k-7,2k-3 are in proportion therefore write them as (k + 2)/(k + 3)  = (2k -3)/(3k - 7)

Now solve for k.

=> (k + 2)(3k -7) = (2k - 3)(k + 3)

=> 3k² -k - 14 = 2k² + 3k - 9

=> k² -4k - 5 = 0  

=> k² - 5k + k - 5 = 0

=> K(k -5) + 1(k - 5) = 0

=> (k + 1)(k - 5) = 0

=> k = -1  or 5