Question

(k-3)x^2 + 4(k-3)x + 4=0.......plz solve it​

Answer 1

Answer:

$(k - 3) {x}^{2} + 4(k - 3)x + 4 = 0$

$(k - 3) {x}^{2} + 2 \times (k - 3)x \times 2 + {2}^{2} = 0$

$(k - 3 + 2) = 0$

$k = 1$

Answer 2

Answer:hope it is helpful for you

Step-by-step explanation: