Question

k-3k²-3k+3k+2k²
What is the answer
Please help me

Answer 1

→Question: k-3k²-3k+3k+2k²

→Solution:

• k²-3k²-3k+3k+2k²
• (k)+(-3k²)+(-3k)+(3k)+(2k²)
• Combine the like terms:
• (-3k²+2k²)+(k+ (-3k)+3k)
• -k²+k is the final answer for k-3k²-3k+3k+2k²

Answer 2

Answer:

k- 3k^2-3k+3k+2k^2

=(k-3k+3k)-(3k^2-2k^2)

=k-k^2

= (-k^2)+k

= -k(k+1)

Hope it helps