Question

k×+3y-(k-3)=0 ,12×+ky-k=0 find value of x?

Answer 1

$\huge{Hey Mate!!!}$

☆☞ Here is ur answer ☜☆

✔✔ For indinte solution,

determinant of coefficient matrix should be zero.

|A|=0

k^2-36=0

k=+6, -6

Another solution, you can use this realtion

For infinte solution

Rank of (A)=Rank of Augmented matrix (A/B) not equal to number of unknowns i.e 2

You will get

K^2-12K+36=0. and K^2-36=0

Solving you will get K=6,-6


HOPE IT HELPS!