Question

(k + 4)³
expand it please for me my exam tommorow​

Answer 1

Answer:-

$\bold{{k}^{3}+ 12{k}^{2}+48k+64}$

Explanation:-

Given:

$({k+4})^{3}$

To Find

expansion of the given expression

Solution

$({k+4})^{3}$

By using the identity

$\boxed{\bold {({x+y})^{3} = {x}^{3}+ {y}^{3}+3xy(x+y)}}$

Here ,

• x = k
• y = 4

On putting the values,

${\rightarrow}{k}^{3}+ {4}^{3}+3(k)(4)(k+4)$

${\rightarrow}{k}^{3}+ 64 +12k(k+4)$

${\rightarrow} {k}^{3}+ 64 +12{k}^{2}+48k$

${\rightarrow}\bold {{k}^{3}+ 12{k}^{2}+48k+64}$

Answer 2

Answer:

Step-by-step explanation:

By using identity (a+b) ^3= a^3+b^3+3ab(a+b)

(K+4) ^3=k^3+4^3+3(k) (4) (k+4)

=k^3+64+12k^2+48k