Question

(k-4)x^2+2(k-4)x+2=0​

Answer 1

Answer:

(k-4)x²+2(k-4)x+2=0

for equal roots DISCRIMINANT ⇒b²=4ac

then a=k-4; b=2(k-4) ;c=2; substituting the values

(2k-8)²=4×(k-4)×2

4k²+64-32k=8k-32

4k²-40k+96=0

k²-10k+24=0

(k-4)(k-6)=0

k=4,6

Step-by-step explanation:

hope it helps!!