(k+4)x^2+(k+1)x+1=0 find the unknown if roots are real and equal
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Answer:
5,-3
Step-by-step explanation:
If roots are real and equal then
D=0
b²=4ac
(k+1)²=4(k+4)(1)
k²+1+2k=4k+16
k²-2k-15=0
k=5,-3
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