Question

(k-4)x2+2(k-4)x+4=0 find the value ​

Answer 1

Answer:

(k-4)x²+2(k-4)x+2=0

IF BOTH THE ROOTS ARE EQUAL;

THEN DISCRIMINANT ⇒b²=4ac.

then a=k-4; b=2(k-4) ;c=2; substituting the values.

(2k-8)²=4×(k-4)×2

4k²+64-32k=8k-32

4k²-40k+96=0

k²-10k+24=0

(k-4)(k-6)=0

k=4,6

Step-by-step explanation:

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