Question

(k+4)x²+(k+1)x+1=0 find the value of k​

Answer 1

Answer:

(k + 4)x² + (k + 1)x + 1 = 0

a = k + 4, b = k + 1, c = 1

For equal roots, discriminant, D = 0

b² - 4ac = 0

(k + 1)² - 4(k + 4) ×1 = 0

k² + 2k + 1 - 4k - 16 = 0

k² - 2k - 15 = 0

k² - 5k + 3k - 15 = 0

k(k - 5) + 3(k - 5) = 0

(k - 5) (k + 3) = 0

k = 5 or k = -3

Thus, for k = 5 or k = - 3, the given quadratic equation has equal roots.