Math, asked by omrai2512, 3 months ago

(k+4) x2 + (k + 1) x+1=0
has equal roots

Answers

Answered by wwwhimanshulothiya25
0

Answer:

no no no

Step-by-step explanation:

noooooooooooonoooooooooooooooooooooo

Answered by vipashyana1
1

Answer:

k=5

Step-by-step explanation:

(k+4)x²+(k+1)x+1=0

a=k+4, b=k+1, c=1

Discriminant=0

b²-4ac=0

(k+1)²-4(k+4)(1)=0

k²+2k+1-4k-16=0

k²+2k-4k+1-16=0

k²-2k-15=0

k²-5k+3k-15=0

(k²-5k)+(3k-15)=0

k(k-5)+3(k-5)=0

(k-5)(k+3)=0

(k-5=0)(k+3=0)

k=5 and k=(-3)

Therefore, the value of k is 5.

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