Question

(k+4) x2 + (k + 1) x+1=0
has equal roots
​

Answer 1

Answer:

no no no

Step-by-step explanation:

noooooooooooonoooooooooooooooooooooo

Answer 2

Answer:

k=5

Step-by-step explanation:

(k+4)x²+(k+1)x+1=0

a=k+4, b=k+1, c=1

Discriminant=0

b²-4ac=0

(k+1)²-4(k+4)(1)=0

k²+2k+1-4k-16=0

k²+2k-4k+1-16=0

k²-2k-15=0

k²-5k+3k-15=0

(k²-5k)+(3k-15)=0

k(k-5)+3(k-5)=0

(k-5)(k+3)=0

(k-5=0)(k+3=0)

k=5 and k=(-3)

Therefore, the value of k is 5.